SSLC Maths NIOS VIII Welcome to your SSLC Maths NIOS VIII Total Questions: 50 Name Mobile No: 1. The angle subtended by a diameter at the circle is 45° 60° 180° 90° None Hint 2. sin²θ + cos²θ = 0 1 −1 2 None Hint 3. In a circle, equal chords subtend ____ angles at the centre. Unequal 90° Equal Zero None Hint 4. Angle subtended by full circle at centre is 270° 360° 180° 90° None Hint 5. In the same segment of a circle, angles are Supplementary Equal Zero Unequal None Hint 6. If arc subtends 80° at centre, angle at circle is 160° 40° 20° 80° None Hint 7. 1 + tan²θ = sin²θ cosec²θ cos²θ sec²θ None Hint 8. 1 + cot²θ = cosec²θ cos²θ tan²θ sec²θ None Hint 9. If angle at centre is 140°, angle at circumference is 280° 140° 35° 70° B) None Hint 10. tan θ = sin θ / ____ sec θ cot θ cosec θ cos θ None Hint 11. If sin θ = 1/2, then cosec θ = 1/2 2 √2 1 None Hint 12. If one angle of a cyclic quadrilateral is 70°, the opposite angle is 90° 110° 180° 70° None Hint 13. In a circle, angle in the same segment theorem is about 90° angles Complementary angles Equal angles Supplementary angles None Hint 14. A quadrilateral inscribed in a circle is called Cyclic quadrilateral Rhombus Parallelogram Rectangle None Hint 15. cot θ = sin θ Perpendicular / Base Base / Perpendicular cos θ None Hint 16. In cyclic quadrilateral, exterior angle equals 90° 180° Opposite interior angle Adjacent angle None Hint 17. If opposite angles of quadrilateral are not supplementary, it is Rectangle Cyclic Parallelogram Not cyclic None Hint 18. In a right triangle, the longest side is called Hypotenuse Altitude Perpendicular Base None Hint 19. A diameter divides a circle into Four parts Three parts Unequal parts Two equal parts None Hint 20. The sum of opposite angles in cyclic quadrilateral is 90° 270° 360° 180° None Hint 21. cos θ = Perpendicular / Hypotenuse Hypotenuse / Base Base / Perpendicular Base / Hypotenuse None Hint 22. Trigonometric ratios depend on Area Size of angle Perimeter Length of sides None Hint 23. In right triangle, sin θ = 4/5, hypotenuse = 5, perpendicular = 5 4 3 2 None Hint 24. sin θ × cosec θ = −1 2 1 0 None Hint 25. If two angles subtend same chord in same segment, they are Zero Equal Double Half None Hint 26. cos θ × sec θ = 2 1 0 −1 None Hint 27. The longest chord of a circle is Tangent Radius Diameter Arc None Hint 28. sec θ = 1 / ____ tan θ sin θ cot θ cos θ None Hint 29. cos θ × sec θ = −1 0 2 1 None Hint 30. A quadrilateral is cyclic if All sides equal Opposite angles are supplementary Diagonals equal All angles 90° None Hint 31. cosec θ = 1 / ____ sin θ cos θ tan θ sec θ None Hint 32. The angle subtended by an arc at the centre is always ____ the angle subtended at the circle. Half of One-third Equal to Twice None Hint 33. If cos θ = 3/5, then sec θ = 2/5 5/3 3/5 5/2 None Hint 34. If diameter is 10 cm, radius is 20 cm 15 cm 5 cm 10 cm None Hint 35. Angle in a semicircle is 45° 60° 90° 180° None Hint 36. If ∠A = 95° in cyclic quadrilateral, opposite angle = 75° 105° 95° 85° None Hint 37. In right triangle, cos θ = 12/13, base = 12, hypotenuse = 13 25 5 12 None Hint 38. Trigonometry is mainly concerned with Circles Polygons Triangles Squares None Hint 39. Opposite angles of a cyclic quadrilateral are Complementary Equal Supplementary 90° None Hint 40. Equal arcs of a circle subtend ____ angles at centre. 180° Unequal Zero Equal None Hint 41. If the angle at centre is 100°, angle at circle on same arc is 200° 25° 100° 50° None Hint 42. If tan θ = 2/3, then cot θ = 2/3 5/6 3/2 1 None Hint 43. tan θ × cot θ = −1 1 2 0 None Hint 44. sin θ = Perpendicular / Hypotenuse Base / Hypotenuse Hypotenuse / Base Base / Perpendicular None Hint 45. Hypotenuse is always opposite to Acute angle Largest angle (90°) Base Smallest angle None Hint 46. sec θ = 1/cos θ 1/sin θ cos θ 1/tan θ None Hint 47. If one angle of cyclic quadrilateral is 120°, adjacent angle may be 120° 100° 80° 60° None Hint 48. The centre of circle lies Outside circle On circumference On chord Inside circle None Hint 49. tan θ = Hypotenuse / Base Base / Hypotenuse Perpendicular / Base Base / Perpendicular None Hint 50. cosec θ = tan θ 1/sin θ 1/tan θ 1/cos θ None Hint Time's up Share: admin Previous post SSLC Maths NIOS VII February 22, 2026
